In triangle ABC, mid points of BC, CA and AB are D, E and F
respectively. FE intersects AD at O. AD = 6cm. Find the length of AO.
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In triangle ABC , as F is midpoint of AB and D is midpoint of BC , we apply the theorem:-
the line segment joining the midpoints of two side of a triangle is parallel to the third side and equal to half of it , we get
=> FD = ½ AC AND FD || AC
also , it is given that E is the midpoint of AC
=> AR = ½AC
from adove two equation , we get , AE = FD
In triangle FOD AND TRIANGLE EOA ,
< FOD= < EOA ( OPPOSITE ANGLE)
FDO = EAO ( AIA AS FD || AE )
ALSO OFD = OEA ( AIA AS FD || AE )
=> triangle FOD = triangle EOA
AO =OD
=> AO = ½AD
=> AO = ½ × 6 = 3 vm
The length of AO is 3 cm
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