In triangle ABC, Mis the mid-point of BC AM is
C
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Answer:
Refering figure,
DE=
2
1
BC
and AP=
2
1
AQ
Given, Area of ΔABC=60cm
2
or
2
1
×BC×AQ=60
or BC×AQ=120
∴ Area of ΔADE=
2
1
DE×AP
=
2
1
×
2
1
BC×
2
1
AQ=
8
1
BC×AQ
=
8
1
×120=15sq.cm.
solution
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