In triangle abc n triangle pqr ab=4cm ,bc = 7cm pq = 6cm qr = 10.5cm find pr if ac = 8cm
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In triangle ABC and triangle PQR we have :
AB/PQ = 4/6 = 2/3
BC/QR = 7/10.5 = 70/105 = 2/3
<B=<Q so the two triangles are similar by SAS there. In similar triangles sides are in proportion.
a)Let PR=x.AC=8cm .Forming the proportion in similar triangles :
4/6 = 8/x
Cross multiplying:
4x=48 or x=12.
b) In similar triangles the ratio of area is equal to square of ratio of proportional sides.
Area of triangle ABC/ Area of triangle PQR = (4/6)^2
= 16/36
= 4/9
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