In triangle abc one angle is 40 degrees if the difference of the other two angles is 30 degrees find both the angles
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Answer:
Let the other two angles be x⁰,y⁰
40 + x + y =180
Since x-y=3
x=30+y
sub it
40+ 30 +y +y =180
70+2y=180
2y=110
y=55⁰
sub y=55 in x-y=30
x-55=30
x=85⁰
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