in triangle ABC, P and Q are points on AB and AC such that PQ parallel to BC.if AP=4 cm ,AQ= 3cm and PB= 2 cm,then find the value of AC
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5
here AC = AQ + QC
AND IF PQ || BC
THEN PB = QC
AND AC = 3+ 2
AC = 5 cm
AND IF PQ || BC
THEN PB = QC
AND AC = 3+ 2
AC = 5 cm
Answered by
0
the answer to your question is 5cm
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