Question

in triangle ABC . P and Q are points on side AB and AC respectively such that PQ parallel BC if AP is equal to 4 cm PB is equal to 6 cm and PQ is equal to 3 cm determine BC​

Answer 1

Answer:

Let ABC be a triangle. Let P,Q are the points on sides AB,BC respectively such that PQ∣∣BC.

Given AP=2cm,PB=4cm,AQ=3cm,QC=6cm.

We have to find BC.

The pictorial representation of the problem is shown below

Since we have PQ∣∣BC we get ΔAPQ∼ΔABC

⇒

AB

AP

=

AC

AQ

=

BC

PQ

Substituting the values we get,

⇒

6

2

=

9

3

=

BC

PQ

⇒

3

1

=

3

1

=

BC

PQ

⇒

3

1

=

BC

PQ

⇒BC=3PQ

Answer 2

$\huge \boxed{ \fcolorbox{u}{blue}{Answer}} \:$

(a) 50%

$\sf{ \cancel{ \frac{50}{100} }} = \frac{1}{2}$

(b) 200%

$\sf{ \cancel \frac{200}{100} } = 2$

(c) 16 ⅔%

$\sf{50\%}$

$\sf{ \cancel\frac{50}{100} } = \frac{1}{2}$