In triangle ABC P and Q are two points on AB and AC respectively such that PQ parallel BC and AP/PB =2/2 then find AQ/QC....
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according to the Theorem of Proportionality,
IF A LINE PARALLEL TO ONE SIDE OF THE TRIANGLE INTERSECTS THE OTHER TWO SIDES OF THE AT DISTINCT POINTS THEN SIDES IN THE ONE HALFPLANE IS PROPORTION TO THE SIDES IN THE OTHER HALFPLANE !!
Thus A-P-B and A-Q-C such that PQ||BC
Hence if AP/PB = 2/2 , then AQ/QC is also equal to 2/2
HOPE IT HELPS !!!
PLEASE MARK MY ANSWER AS BRAINLIEST !!!
IF A LINE PARALLEL TO ONE SIDE OF THE TRIANGLE INTERSECTS THE OTHER TWO SIDES OF THE AT DISTINCT POINTS THEN SIDES IN THE ONE HALFPLANE IS PROPORTION TO THE SIDES IN THE OTHER HALFPLANE !!
Thus A-P-B and A-Q-C such that PQ||BC
Hence if AP/PB = 2/2 , then AQ/QC is also equal to 2/2
HOPE IT HELPS !!!
PLEASE MARK MY ANSWER AS BRAINLIEST !!!
shubham610:
yrr solve krna tha
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I hope answer is helpful to us
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