Math, asked by shubham610, 11 months ago

In triangle ABC P and Q are two points on AB and AC respectively such that PQ parallel BC and AP/PB =2/2 then find AQ/QC....

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Answered by NandilGhediya
4
according to the Theorem of Proportionality,

IF A LINE PARALLEL TO ONE SIDE OF THE TRIANGLE INTERSECTS THE OTHER TWO SIDES OF THE AT DISTINCT POINTS THEN SIDES IN THE ONE HALFPLANE IS PROPORTION TO THE SIDES IN THE OTHER HALFPLANE !!

Thus A-P-B and A-Q-C such that PQ||BC

Hence if AP/PB = 2/2 , then AQ/QC is also equal to 2/2


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shubham610: yrr solve krna tha
NandilGhediya: kar to diya
shubham610: are yr kaise solve hoga... av ye to poora likhna nhi h
NandilGhediya: to sidha likh do k according to thales theorem AP/PB = AQ/QC hence AQ/QC = 2/2
shubham610: thanks..
Answered by Anonymous
3

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I hope answer is helpful to us

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