in triangle abc p and q points on equal sides ab =ac of triangle abc such that ap =aq prove that co =bq
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given AB=AC AND AP=AQ
THUS AB-AP=AC-AQ
BP=CQ FIGURE
NIW THE N ∆BCP AND ∆BCQ
BP=CQ
ANGLE C =ANGLE C (COMMON)
AND BC=BC (SAS CONGRENT)
NOW (BQ=CP) corresponding part of congrevent triangle
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