in triangle ABC p is a orthocenter.then p.t AB+BC+CA<2(PA+PB+PC)
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Answer:
We know that,
PG=2G0 where G is the centroid of the triangle.
Let a point D between B and C
So, OD=(OB+OC)/2
now, OA+OB+OC=OA+20D
We know that G divide the point A and mid-point of appoicte side D in ratio 2:1
So, OG=
2+1
(OA+20D)
So, OA+OB+OC=30G
=20G+OG
=GP+OG=OP
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