Question

In triangle ABC, P is a point on BC . Such that BP : PC = 3 : 4 and Q is the midpoint of BP. Then the area of triangle ABQ = area of Triangle ABC is equal to ___________________ ?

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Answer 1

Let A be area of triangle ABC.

BC = BP+PC = 4x+11x as given that BP:PC =4:11

=> x = BC /15

BP = 4x =. 4*BC/15

As Q is mid pt of BP

BQ = 2* BC / 15.

So Area of ABQ = (2/15) * A