Question

In triangle abc p is a point on side bc such that angle cap = angle b. Prove that angle apc = angle bac

Answer 1

from triangle apc and bac,
angle p = angle p (90)
ap =ap (common side)
angle a = angle p (given)

thus,
triangle apc is congruent to bac

Answer 2

Given= angleCAP=angleB

T.P=angleAPC=angleBAC

IN triangle APC and triangle BAC

angleA=angleB (given)
AC=AC(common)
AngleB =AngleC

Triangle APC Congress Triangle BAC

Angle APC =Angle BAC (c.p.c.t)