in triangle ABC, P is midpoint of AB and Q is midpoint of AC. If AB =9.6cm BC=12cm and AC =11.2cm find the perimeter of the trapezium.
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Answer:
26.9 cm
Step-by-step explanation:
As P is the midpoint of AB,
∴PB=(1/2)(AB)=9.6/2=4.8cm
As Q is the midpoint of AC,
∴CQ=(1/2)(AC)=11.2/2=5.6cm
Also, PQ will be parallel to BC from the midpoint theorem.
∴PQ=(1/2)(BC)=11/2=5.5cm
∴ Parimeter of trapezium
=PB+BC+CQ+PQ
=4.8+5.6+5.5+11
=26.9cm
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