In triangle ABC, P, Q and R are the midpoints of AB, AC, and BC. AB = 10cm, BC = 12cm and AC = 8cm. (i) What is the length of PQ? *
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Answer:
If R, Q and P are the midpoints of AB, AC and BC, and by applying the theorem:-
The line segment joining the midpoints of two side of a triangle is parallel to the third side and equal to half of it, we get
PQ=
2
1
AB=AR and PQ∣∣AR
PQ=
2
1
AC=AQ and PR∣∣AQ
Since the above conditions are sufficient for a parallelogram, therefore ARPQ is a parallelogram.
∴ Perimeter of ∥
gm
=ARPQ=2(AR+AQ)=AB+AC=(30+21)cm=51cm
solution
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