Question

In
triangle ABC, P, Q and R are the
the midpoints of AB, BC and CA respectively.
AB= I2 cm, BC = 16 cm and CA = 20 cm, find the perimeter of trapezium PBCR.​

Answer 1

Answer:

40 cm

Step-by-step explanation:

PR II BC, PR=1/2 BC. ( MID POINT THEOREM)

PR = 1/2 * 16 (BC= 16 cm)

PR = 8 cm

PB = 6 cm (•.• P is the mid point of AB)

RC = 10 cm (•.• R is the mid point of AC)

perimeter of trapezium = Sum of all sides

= PR + RC + CB + BP

=> 8 + 10 + 16 + 6

= 40

ans. 40 cm

Answer 2

Answer:

P and R are the mid point of the sides AB and AC respectively.

By mid point theorem

PR =1/2BC

=>PR =1/2 ×16

=>PR =8

PB=1/2AB and RC =1/2AC(P and R are the mid point of the sides AB and AC respectively. )

=>PB=1/2×12 and RC=1/2×20

=>PB=6 and RC = 10

Now,perimeter of of trapezium = sum of the all sides.

=6+8+10+16

=40cm

Step-by-step explanation: