In triangle ABC, P, Q, R lie on sides BC, CA & AB. If BP = PC, PQ ║ AB & QR ║ BC, prove that RP ║ CA
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In a triangle line joining mid - point of two sides are parallel and half of third side
PQ∥AB
PQ=
2
1
AB→(i)
QR∥BC
QR=
2
1
BC→(ii)
PR∥AC
PQ=
2
1
AC→(iii)
fromequation(i)(ii)
two pairs are parallel so, BPQR is a parallelogram
BP=QR=
2
BC
→(iv)
In parallelogram diagonals bisects each other so
X is mid -point to PR. Similarly,
Y is mid- point on QP
InΔRPQ
XY=
2
1
QR
XY=
2
1
(
2
1
BC)
4
1
BC
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