Question

In triangle ABC point D is on side BC is such that DC=8 and BC=18.Find area of triangle ABD: area of triangle ACD? *



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Answer 1

Question:-

In triangle ABC point D is on side BC is such that DC=8 and BC=18.

Find:-

Find area of triangle ACD.

Step-by-step explanation:

➤It is given that D is a point on BC such that LABD=LCAD.

➤Now, From AACD and ABCA, we have

→LACD-BCA (Common angle)

→LABD=LCAD (Given)

➤By AA similarity, AACD is similar to ABCA.

Thus, it

15 4BC

BC = 3.75

➤Now, aAACD aABCA ---

→(Because of theorem of area of similar triangles)

Hence, areaAACD=16cm^12 and areaABCA=25cm^2

Answer 2

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