Question

in triangle abc point d on side bc is such that dc-4 bc-12 find area triangle abd and area of triangle adc​

Answer 1

Answer:

Step-by-step explanation:

ΔABC, ΔABD, ΔADC all have same height 'h'.

Base length of ΔABC = 15

Base length of ΔABD = 9

Base length of ΔADC = 6

Area of ΔABC= 1/2 × h ×15

Area of ΔABD= 1/2 × h ×9

Area of ΔADC= 1/2 × h ×6

A(ΔABD) : A(ΔABC) = (1/2 × h ×9):(1/2 × h ×15) = 3:5

A(ΔABD) : A(ΔADC) = (1/2 × h ×9):(1/2 × h ×6) = 3:2