In triangle,ABC, points X, Y, Z are the midpoints
of sides AB, BC and AC respectively. If AB =21
BC = 30 and AC = 15, then find perimeter of triangle XYZ
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since X, Y, Z are mid points of sides AB, BC and AC then ,
XY, YZ and XZ would be parallel to sides AC, AB and BC respectively and would the length would be half of the sides. i. e
XY= 7.5
YZ= 10.5
XZ=15
so, perimeter of ∆ XYZ = 10.5+15+7.5= 33
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