Question

in triangle abc,pq is parallel to ab .if cp/pa= 3/1 and area of triangle anc=64cm^2 .find the area 0f the quadrilateral abqp​

Answer 1

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Answer 2

Answer:

According to question,

PB

AP

=

QC

AQ

=

2

1

[basic proportionality theorem]

2

1

=

QC

3

QC =6

Hence, AC = AQ + QC = 3+6=9 cm