Math, asked by Raviuser017, 7 months ago

In triangle ABC prove that a square sin(b-c)+b square sin(c-a)+c square sin(a-b)=0

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Answered by Anonymous
4

sin and cosine are functions revealing the shape of a triangle looking out from a vertex with angle sin is the ratio of opposite side to the hypotenuse while cos is the ratio of the adjacent side to the hypotenuse

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