Question

In triangle ABC prove that AB+BC+CA>2AB

Answer 1

Hola Mate !!

Here's your answer :-

since the sum of two sides in a triangle is greater than the third one.
BC + CA > AB

adding AB on the both sides of the inequality:

we get ,
AB + BC + CA > AB + AB
=> AB + BC + CA > 2AB
which is the required result.

hope this helps you.

cheers!!

$mark \: me \: as \: brainliest$

Answer 2

Answer:

since the sum of two sides in a triangle is greater than the third one.

BC + CA > AB

adding AB on the both sides of the inequality:

we get ,

AB + BC + CA > AB + AB

=> AB + BC + CA > 2AB

which is the required result.

hope this helps you.

cheers!!