Question

In triangle abc prove that cos a + b + cos c is equal to zero

Answer 1

Answer:

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Step-by-step explanation:

By angle sum property of triangles, <A + <B + <C = 180 deg

So, (A + B) = 180 - C

==> cos(A + B) = cos(180 - C) = -cos(C)

So, cos(A + B) + cos(C) = 0 [Proved]

Answer 2

Answer:

answer is 0

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