Question

In triangle abc prove that cos square A by 2 + cos square B by 2 + cos square C by 2 equal to 2 + 2 sin a by 2 Sin B by 2 Sin C by 2

Answer 1

Answer:

tanA+tanB+tanC/2cos

Step-by-step explanation:

Cos2A+2cos2B+2cos2C=2sinA+2sinB+2sinc/2

Cos(cosA+2cosB+2cosC) =2(sinA+sinB+sinC) /2

cos=sinA+sinB+since/cosA+2cosB+2cosC

Cos=tanA+tanB+tanC/2

tanA+tanB+tanC/2cos