Math, asked by chidhekar, 1 year ago

in triangle ABC ,prove that r1+r2+r3-r=4R

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Answered by dilisha21meena
5

Step-by-step explanation:

L.H.S = r1 + r2 + r3 – r = 4R = 2acosecA ∵ a/Asin = 2R = acosecA = R.H.S. Hence L.H.S. = R.H.SRead more on Sarthaks.com - https://www.sarthaks.com/311241/in-a-abc-prove-that-r1-r2-r3-r-4r-2a-coseca

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