Question

in triangle abc prove that : sec(B+C/2)=cosecA+2​

Answer 1

Answer:

triangle abc

sec(b+c/2)

=>cosec(90-b-c/2)

as it is a triangle a=180-b-c=90-b-c/2                                        =>1

therefore sec(b+c/2)=cosec(a/2)