in triangle ABC prove that sin (A+B]=SIN C
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in a triangle A + B + C = 180 deg.
A + B = 180 - C
we know that Sin (X) = Sin (180 - X)
So Sin (A + B) = Sin (180 - C) = Sin C
A + B = 180 - C
we know that Sin (X) = Sin (180 - X)
So Sin (A + B) = Sin (180 - C) = Sin C
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