In triangle ABC prove the following
c-bcos A/b-cCOS A = cos B/ cos C
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Answer:
Step-by-step explanation:
c - bcos A / b - ccos A = cos B/ cos C
By the projection formula:
c = bcosA + acosB and b = ccosA + acosC
Therefore, c - bcosA = acosB and b - ccosA = acosC
Therefore, (c - bcosA)/(b - cosA) = cosB/cosC
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