Question

In triangle ABC prove the following
c-bcos A/b-cCOS A = cos B/ cos C​

Answer 1

Answer:

Step-by-step explanation:

c - bcos A / b - ccos A = cos B/ cos C

By the projection formula:

c = bcosA + acosB and b = ccosA + acosC

Therefore, c - bcosA = acosB and b - ccosA = acosC

Therefore, (c - bcosA)/(b - cosA) = cosB/cosC