Math, asked by jubinjoy432ou61r2, 1 year ago

In triangle ABC, ray AD bisects angle A and intersects BC in D. If BC = a, AC = b and AB =c, prove that BD = ac/(b+c)

Answers

Answered by kaushik51
59
hope this helps you .............
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jubinjoy432ou61r2: Thnx
jubinjoy432ou61r2: How AC/AB = DC/BD? Is it because you proved similarity of triangles?
kaushik51: yes
jubinjoy432ou61r2: Thnx
Answered by SerenaBochenek
20

Answer:

The proof is explained below.

Step-by-step explanation:

Given that in triangle ABC, ray AD bisects angle A and intersects BC in D. If BC = a, AC = b and AB =c,

we have to prove that BD=\frac{ac}{b+c}

Since AB bisects ∠A

\frac{AC}{AB}=\frac{DC}{BD}

\frac{b}{c}=\frac{DC}{BD}

\frac{b}{c}+1=\frac{DC}{BD}+1

\frac{b+c}{c}=\frac{BC}{BD}=\frac{a}{BD}

BD=\frac{ac}{b+c}

Hence proved

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