Question

In triangle ABC, right anged at B, AB=5cm and angleACB= 3C, find BC and AC

Answer 1

Answer:

hopes its helpful I find its solution at google

Answer 2

Answer:

sin$=Sin30°=1/2=AB/AC=5/AC

So,AC=10cm.

By pythogoras theorem,(10)2-(5)2=(BC)2

So BC=Root50.