Question

In triangle ABC right angle at B if AB=5 , BC=8 then find all the fundamental ratios with reference to angle C_​

Answer 1

Step-by-step explanation:

Given: angle B=90° ,AB=5, BC=8.

By Pythagoras theorem:

AC²=AB²+BC²=>5²+8²=>25+64=89

AC=√89.

Angle C= theta:

sin C=AB/AC=5/√89.

cos C=BC/AC=8/√89.

tan C=AB/BC=5/8.

cosec C=AC/AB=√89/5.

sec C=AC/BC=√89/8.

cot C=BC/AB=8/5.

Hope helps u.

Answer 2

Step-by-step explanation:

With reference to ∠B, we have

Base = AB = 5, Perpendicular = AC = 12 and,

Hypotenuse = BC = 13

∴sinB=

BC

AC

=

13

12

and, tanB=

AB

AC

=

5

12

With reference to ∠C, we have

Base = AC = 12, Perpendicular = AB = 5 and, Hypotenuse = BC = 13

∴cosC=

BC

AC

=

13

12

solution