In triangle ABC, right angle at B, if tanA = 1√3, find sinA.cosC + cosA.sinC
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Answer:
1
Step-by-step explanation:
sin A * cos C + cos A * sin C = sin(A+C)
since B=90 (B is right angle)
A+C=90 (angle sum property of triangle)
sin(A+C)=sin 90=1
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Find A from tanA and then put the values
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