Question

In triangle ABC right angle at C then value of cosec square A - tan square B is equal to

Answer 1

Answer:

${cosec}^{2} a - {tan}^{2} a = .....$

${cosec}^{2} a = \frac{hypoteneus}{opposite} = \frac{ \sqrt{3} }{ \sqrt{3} } = 1$

${tan}^{2} a = \frac{opposite}{adjecent} = \frac{ \sqrt{3} }{1} = \sqrt{3}$

${cosec}^{2} a - { \tan }^{2} a \\ = 1 - \sqrt{3}$