Question

in triangle ABC right angle is at B .If AC is 24 cm and AB is 10 cm Find BC​

Answer 1

In triangle ABC,

Angle ABC=90°

by the pythagoras theorem,

AC^2=AB^2+BC^2

24^2=10^2+BC^2

576=100+BC^2

BC^2=576-100

BC^2=476

BC=21.8

Answer 2

Given: Angle B is 90°.

AC is 24 cm.

AB is 10 cm.

To find: BC is?

Solution: By pythagoras theorem

AC^2 = AB^2 + BC^2

24^2 = 10^2 + BC^2

576 = 100 + BC^2

BC^2 = 576 - 100

BC^2 = 476

BC= 21.817

Hence, BC is 21.8 cm.

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