Question

in triangle ABC , right angled at A , having AB=5cm , and BC=12cm , find sinB , cosC , and tanB​

Answer 1

Answer:

With reference to ∠B, we have

Base = AB = 5, Perpendicular = AC = 12 and,

Hypotenuse = BC = 13

sinB = AC/ BC = 13/12

and, tanB = AB/ AC = 5/12

With reference to ∠C, we have

Base = AC = 12, Perpendicular = AB = 5 and, Hypotenuse = BC = 13

cosC = BC/ AC = 13/12

hope it helps you.....