Question

In triangle ABC right angled at A, tan C = root 3, find sinB CosC + cos B sinC

Answer 1

tanC=√3=tan60°
so,C=60°
and A=90°[given]
B=30°
now
sinBcosC+cosBsinC
=sin30°cos60°+cos30°sin60°
=1/2+1/2+√3/2+√3/2
=1+√3

hope you're satisfied

Answer 2

Answer:

Step-by-step explanation:

It is given that tanC=√3 means tanC=tan60°

So,C=60° and

A=90° (given)

B=30°

Now,

sinB.cosC+cosB.sinC

1/2+1/2+√3/2+√3/2

1+√3 ANSWER