Question

In triangle ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine : (i) sin A, cos A (ii) sin C, cos C

Answer 1

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Answer 2

$\huge\textbf{Solution :}$


In Δ ABC, right-angled at B

Using Pythagoras theorem

AC² = AB² +BC²  

AC² = 576 + 49 = 625

AC = √635

AC = ±25

$AC\:=\:+ 25$

Now

(i) In a right angle triangle ABC where B=90° ,

Sin A = $\frac{BC}{AC}$

= $\frac{7}{25}$

CosA = $\frac{AB}{AC}$

= $\frac{24}{25}$

(ii) Sin C = $\frac{AB}{AC}$

= $\frac{24}{25}$

Cos C = $\frac{BC}{AC}$

= $\frac{7}{25}$