Question

in triangle abc right angled at b AB =24 cm BC = 7 cm determine (a) sin a ,cos b. (b) sinc, cosc

Answer 1

thanks. ....................

Answer 2

In Δ ABC, right-angled at B

Using Pythagoras theorem

AC² = AB² +BC²  

AC² = 576 + 49 = 625

AC = √635

AC = ±25

$AC\:=\:+ 25$

Now

(i) In a right angle triangle ABC where B=90° ,

Sin A = $\frac{BC}{AC}$

= $\frac{7}{25}$

CosA = $\frac{AB}{AC}$

= $\frac{24}{25}$

(ii) Sin C = $\frac{AB}{AC}$

= $\frac{24}{25}$

Cos C = $\frac{BC}{AC}$

= $\frac{7}{25}$