in triangle ABC right angled at B,AB=24cm,BC=7cm determine sin C, cosC
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Given AB=24cm, BC=7cm
By Pythagoreas theorem
AC^2=AB^2+BC^2
AC^2=24^2+7^2
AC^2=576+49
AC^2=625
AC=25cm
sinC=AB/AC
=24/25
cosC=BC/AC
=7/25
By Pythagoreas theorem
AC^2=AB^2+BC^2
AC^2=24^2+7^2
AC^2=576+49
AC^2=625
AC=25cm
sinC=AB/AC
=24/25
cosC=BC/AC
=7/25
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