in triangle
ABC right angled
at B, AB = 5
and sinc = 1/2 find AC
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छठतठदठक्षफलप ठ
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Answer:
opposite to point c is AB and hypotenuse is AC
sinc = opp/hyp =AB/AC
1/2=5/hyp
therfore hypotenuse is 10cm and therfore AC is 10cm
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