Question

In triangle ABC right angled at B . AB=5cm and angle ACB =30` determine
the lengths of the sides BC and AC.


​

Answer 1

Hope this helps.

Kindly mark my answer as BRAINLIEST.....

Answer 2

Answer:

BC = 5√3cm

AC = 10cm

Given:

∠ABC = 90°

∠ACB = 30°

AB = 5cm

To Find:

BC and AC

Solution:

Finding AC

$\sf sin30 ^\circ = \dfrac{AB}{AC}$

$\sf \dfrac{1}{2} = \dfrac{5}{AC}$

AC = 10cm

Finding BC

$\sf cos30^ \circ = \dfrac{BC}{AC}$

$\sf\dfrac{\sqrt{3}}{2} = \dfrac{BC}{10}$

2BC = 10√3

$\sf BC = \dfrac{10\sqrt{3}}{2}$

BC = 5√3