Question

in triangle abc right angled at b ab=5cm and angle acb = 30 degree find bc and ac

Answer 1

Hi ,

In Triangle ABC ,

< B = 90°

AB = 5cm

< ACB = 30°

hypotenuse = AC

i ) sin 30° = AB / AC

1/2 = 5 / AC

AC = 5 × 2

AC = 10

ii ) cos 30° = BC / AC

√3 / 2 = BC / 10

10√3 / 2 = BC

5√3 = BC

BC = 5√3

Therefore ,

AC = 10,

BC = 5√3

I hope this helps you.

:)

Answer 2

Answer:

1. The first picture has according to the question.
2. The second picture has answer.
3. The last picture has completed figure according to the answers

Step-by-step explanation:

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