In Triangle ABC right angled at B
AB= 5cm and angleACB - 30°
Determine the lengths of the
side BC and AC
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Answer:
given,In∆ABC
AB=5cm,
angleACB=30°
then,
BC=?,
AC=?
sin(theta)=opp.side÷hypotenuse
sin30°=AB÷AC
1÷2=5÷AC
AC=5×2
AC=10
tan(theta)=opp.side÷adj.side
tan30°=AB÷BC
1÷√3=5÷BC
BC=5√3
therefore,AC=10,BC=5√3
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