Question

In triangle abc right angled at b ab=7cm and (ac-bc) =1cm. Find the value of sin c and cosc. ​

Answer 1

Answer:

Step-by-step explanation:

BC = 7cm

Let,

AC =x+1

AB = x

By Pythagoras theorem

In triangle ABC

(AB)^2 + (BC)^2 =(AC)^2

(7)^2 + (x)^2 = ( x+ 1)^2

49 + x^2 = x^2 + 1 +2x

X^2 -x^2 -2x = -49 + 1

-2x = -48

2x = 48

x =48/2

x = 24

Answer 2

A theorem in geometry: the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.

Given$=ab=7cm,ac-bc=1cm$

Find the value of $sin C$ and $cos C$.

According to the question

Let $bc=x$

$ac=xH.cm$

$ab=7cm$

Apply pythagoras theorem

$(AC)^2=(AB)^2+(BC)^2$

$x^2+1+2x=x^2+49$

$2x=48$

$x=24$

$BC=24$

$AC=24H=25cm$

Now, $sinC=\frac{P}{H} =\frac{7}{25}$

$cosC=\frac{B}{H}=\frac{24}{25}$