Question

in triangle abc right angled at B, AB+ AC = 24 cm and BC =2 cm determine the value of sin A , TanA ,Sec A, Tan C​

Answer 1

Answer:

AB+AC= 24

BC= 2CM

AC2 = AB2+BC2

AC2-AB2= 4

(AC-AB)(AC+AB) = 4

(AC-AB) = 4/24

AC- AB = 1/6

6AC-6AB= 1

6 AC+ 6 AB= 24× 6CM

12AC= 144

AC = 12CM

AB= 12CM

SIN@= p/h

= BC/AC

= 1/6

tan @ = 1/6

sec A = 6/1

tan c = 6/1