in triangle abc right angled at B, AB+ AC = 24 cm and BC =2 cm determine the value of sin A , TanA ,Sec A, Tan C
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Answer:
AB+AC= 24
BC= 2CM
AC2 = AB2+BC2
AC2-AB2= 4
(AC-AB)(AC+AB) = 4
(AC-AB) = 4/24
AC- AB = 1/6
6AC-6AB= 1
6 AC+ 6 AB= 24× 6CM
12AC= 144
AC = 12CM
AB= 12CM
SIN@= p/h
= BC/AC
= 1/6
tan @ = 1/6
sec A = 6/1
tan c = 6/1
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