Question

in triangle ABC, right - angled at B ; and AB = 15cm , AC = 17 cm; find : cos c and cosec A ​

Answer 1

ac2 = ab2 + bc2

17×17= 15×15+ bc2

289=225+ bc2

289-225= bc2

64 =bc2

8 = bc

cos=a/H =8/17

cosec=H/o 17/15

Answer 2

Cos15/17

Cosec=17/8

This problems are related to trigonometry