Question

In triangle ABC right angled at B, BC=7cm, AC-AB=1cm, then find the value of
(i) cosA+sinA (ii) tan C - cosecA+sinC.cosA (iii) tanA.secC

Answer 1

Answer:

AC is hypotenuse, therefore

AC^2=AB^2+BC^2

AC-AB=1

AC=AB+1

(AB+1)^2=AB^2+BC^2

AB^2+2.AB+1=7^2+AB^2

2.AB=48

AB=24

AC=24+1=25

cos A + sin A=24/25+5/25=29/25