Question

In triangle ABC, right angled at B, BD perpendicular to AC,Prove that BD^2 =AD*DC

Answer 1

First proof both the traingles to be to be similar.

Then by side ratio , cross multiply.

you'll get the answer.

Answer 2

Solution :-

A = M , B = N , C = P , D = Q

In ∆CBD and ∆BAD we have,

→ ∠CDB = ∠BDA { Given that BD ⟂ AC .}

→ ∠BCD = ∠ABD

So,

→ ∆CBD ~ ∆BAD { By AA similarity. }

then,

→ CD/BD = BD/AD

→ BD² = AD * CD

→ BD² = AD * DC { proved. }

Learn more :-

In the figure ∠ MNP = 90°, ∠ MQN = 90°, , MQ = 12 , QP = 3 then find NQ .

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show that AB2 = AD.AC

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