Question

In triangle ABC, right angled at B if sin A = 1/2, find the value of
sin C cos A - cos C sin A​

Answer 1

Answer:

1/2  

Step-by-step explanation:

Given, the triangle is right angled at B, (ie., ∠B=90° )

=> the sides other than the hypotenuse AC are AB  and BC

given sinA = 1/2  

=> ∠A = 30°  ( as sin30° =  1/2  )

=> ∠C = 180° - (∠A+∠B)

            = 180° - (30+90)°

            = 180° - 120°

     ∠C = 60°

now consider, sin C cos A - cos C sin A​

= sin (C-A)

= sin (60°-30°)

= sin30°

= 1/2