In triangle ABC, right angled at B if sin A = 1/2, find the value of sin C cos A – cos C sin A
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Given B=90 and sinA=1/2
then. A=30
so C=180-B-C
C=180-120=60
sinCcosA-cosCsinA=sin(C-A)=sin30=1/2
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1/2
we used the pythagoras theorem , in the traingle
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