In triangle ABC, right angled at B if sin A = 1/2, find the value of :sin C cos A
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Answer:
given sin A =1/2 A is 30 degrees angle B is 90 degrees
then value of angle C is 180-(90+30)=60 degrees
sin C is sin 60 is √3/2
cos C is cos 60 1/2
sin A is sin 30 =1/2
cos A is cos 30= √3/2
sinC.cosA-cosC.sinA=√3/2*√3/2-1/2*1/2
=3/4-1/4-1/2
cos A.cosC+ sinA.sinC=√3/2*1/2+1/2*√3/2
= √3/4+√3/4=2√3/4=√3/2
Hope it helps you
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Answer:
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